SSSRFinder and Ring Equivalence Classes

With hubris and arrogance, I implemented my own ring equivalence class finder. With humility and grace, the SSSRFinder method getRingEquivalenceClasses does better for at least one case:

This is the test case used in SimpleCycleBasisTest, and probably in the paper on the subject. I guess I should read that instead of other papers on cycle bases. I do get the same answer for cuneane as when I do it by hand. That is to say, 3 equivalence classes with [1, 2, 2] elements.

For the 'Bauer' graph above (as I am currently calling it - Ulrich Bauer is the author of the SSSRFinder) the signature method puts almost every vertex in its own equivalence class. Now my method makes equivalence classes from cycles with the vertices in the same vertex equivalence class. Naturally enough, this makes a lot of ring equivalence classes.

The graph on the left has vertices colored by degree, to show how dissimilar the rings are. Is the SSSRFinder really getting the right answer?

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chalky

I wanted to show something that hints at the things that the new architecture can afford us: This is using a Java2D graphics Paint object to make it look like chalk...kindof. It's a very simplistic way of doing it by making a small image with a random number of white, gray, lightgray, and black pixels. edit: it doesn't look so good at small scales some tweaking of stroke widths and so on is essential.

The Gale-Ryser Theorem

This is a small aside. While reading a paper by Grüner, Laue, and Meringer on generation by homomorphism they mentioned the Gale-Ryser (GR) theorem. As it turns out, this is a nice small theorem closely related to the better known Erdős-Gallai (EG). So, GR says that given two partitions of an integer ( p and q) there exists a (0, 1) matrix A iff p* dominates q such that the row sum vector r(A) = p and the column sum vector c(A) = q . As with most mathematics, that's quite terse and full of terminology like 'dominates' : but it's relatively simple. Here is an example: The partitions p and q are at the top left, they both sum to 10. Next, p is transposed to get p* = [5, 4, 1] and this is compared to q at the bottom left. Since the sum at each point in the sequence is greater (or equal) for p* than q , the former dominates. One possible matrix is at the top left with the row sum vector to the right, and th...

1,2-dichlorocyclopropane and a spiran

As I am reading a book called "Symmetry in Chemistry" (H. H. Jaffé and M. Orchin) I thought I would try out a couple of examples that they use. One is 1,2-dichlorocylopropane : which is, apparently, dissymmetric because it has a symmetry element (a C2 axis) but is optically active. Incidentally, wedges can look horrible in small structures - this is why: The box around the hydrogen is shaded in grey, to show the effect of overlap. A possible fix might be to shorten the wedge, but sadly this would require working out the bounds of the text when calculating the wedge, which has to be done at render time. Oh well. Another interesting example is this 'spiran', which I can't find on ChEBI or ChemSpider: Image again courtesy of JChempaint . I guess the problem marker (the red line) on the N suggests that it is not a real compound? In any case, some simple code to determine potential chiral centres (using signatures) finds 2 in the cyclopropane structure, and 4 in the ...

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